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67850113 is a prime number
BaseRepresentation
bin1000000101101…
…00111110000001
311201200010212011
410002310332001
5114332200423
610422132521
71452500512
oct402647601
9151603764
1067850113
1135332881
121a881141
13110980c6
149022a09
155e53b0d
hex40b4f81

67850113 has 2 divisors, whose sum is σ = 67850114. Its totient is φ = 67850112.

The previous prime is 67850071. The next prime is 67850141. The reversal of 67850113 is 31105876.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 63552784 + 4297329 = 7972^2 + 2073^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-67850113 is a prime.

It is a super-2 number, since 2×678501132 = 9207275668225538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (67850513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a good prime.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33925056 + 33925057.

It is an arithmetic number, because the mean of its divisors is an integer number (33925057).

Almost surely, 267850113 is an apocalyptic number.

It is an amenable number.

67850113 is a deficient number, since it is larger than the sum of its proper divisors (1).

67850113 is an equidigital number, since it uses as much as digits as its factorization.

67850113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5040, while the sum is 31.

The square root of 67850113 is about 8237.1180032825. The cubic root of 67850113 is about 407.8653939692.

Adding to 67850113 its reverse (31105876), we get a palindrome (98955989).

The spelling of 67850113 in words is "sixty-seven million, eight hundred fifty thousand, one hundred thirteen".