Base | Representation |
---|---|
bin | 10011110110010010011… |
… | …10010011000000111011 |
3 | 2102012022102012020202021 |
4 | 21323021032103000323 |
5 | 42133144041113313 |
6 | 1241144143215311 |
7 | 100162056106621 |
oct | 11731116230073 |
9 | 2365272166667 |
10 | 681980801083 |
11 | 24325442386a |
12 | b0209ba7537 |
13 | 4c406276a6a |
14 | 2501811b511 |
15 | 12b171aa78d |
hex | 9ec939303b |
681980801083 has 2 divisors, whose sum is σ = 681980801084. Its totient is φ = 681980801082.
The previous prime is 681980800997. The next prime is 681980801093. The reversal of 681980801083 is 380108089186.
681980801083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 681980801083 - 213 = 681980792891 is a prime.
It is a super-3 number, since 3×6819808010833 (a number of 36 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 681980801083.
It is not a weakly prime, because it can be changed into another prime (681980801093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 340990400541 + 340990400542.
It is an arithmetic number, because the mean of its divisors is an integer number (340990400542).
Almost surely, 2681980801083 is an apocalyptic number.
681980801083 is a deficient number, since it is larger than the sum of its proper divisors (1).
681980801083 is an equidigital number, since it uses as much as digits as its factorization.
681980801083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 663552, while the sum is 52.
The spelling of 681980801083 in words is "six hundred eighty-one billion, nine hundred eighty million, eight hundred one thousand, eighty-three".
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