Base | Representation |
---|---|
bin | 111111100111101011… |
… | …111001101011101001 |
3 | 20112022202020112110221 |
4 | 333213223321223221 |
5 | 2104400224223133 |
6 | 51214253410041 |
7 | 4635552430606 |
oct | 774753715351 |
9 | 215282215427 |
10 | 68311554793 |
11 | 26a75101209 |
12 | 112a5499921 |
13 | 65986b5551 |
14 | 344069b6ad |
15 | 1b9c290a2d |
hex | fe7af9ae9 |
68311554793 has 2 divisors, whose sum is σ = 68311554794. Its totient is φ = 68311554792.
The previous prime is 68311554781. The next prime is 68311554809. The reversal of 68311554793 is 39745511386.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 68310617769 + 937024 = 261363^2 + 968^2 .
It is a cyclic number.
It is not a de Polignac number, because 68311554793 - 25 = 68311554761 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 68311554793.
It is not a weakly prime, because it can be changed into another prime (68311551793) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34155777396 + 34155777397.
It is an arithmetic number, because the mean of its divisors is an integer number (34155777397).
Almost surely, 268311554793 is an apocalyptic number.
It is an amenable number.
68311554793 is a deficient number, since it is larger than the sum of its proper divisors (1).
68311554793 is an equidigital number, since it uses as much as digits as its factorization.
68311554793 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2721600, while the sum is 52.
The spelling of 68311554793 in words is "sixty-eight billion, three hundred eleven million, five hundred fifty-four thousand, seven hundred ninety-three".
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