Base | Representation |
---|---|
bin | 10011111000110101110… |
… | …01110001101011110001 |
3 | 2102022211220202100201112 |
4 | 21330122321301223301 |
5 | 42144000343402033 |
6 | 1241532134443105 |
7 | 100241035652066 |
oct | 11743271615361 |
9 | 2368756670645 |
10 | 683351153393 |
11 | 243897a02837 |
12 | b0530b03495 |
13 | 4c594144a0c |
14 | 25108112c6d |
15 | 12b97645c48 |
hex | 9f1ae71af1 |
683351153393 has 2 divisors, whose sum is σ = 683351153394. Its totient is φ = 683351153392.
The previous prime is 683351153281. The next prime is 683351153447. The reversal of 683351153393 is 393351153386.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 683031172849 + 319980544 = 826457^2 + 17888^2 .
It is a cyclic number.
It is not a de Polignac number, because 683351153393 - 210 = 683351152369 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (683351150393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 341675576696 + 341675576697.
It is an arithmetic number, because the mean of its divisors is an integer number (341675576697).
Almost surely, 2683351153393 is an apocalyptic number.
It is an amenable number.
683351153393 is a deficient number, since it is larger than the sum of its proper divisors (1).
683351153393 is an equidigital number, since it uses as much as digits as its factorization.
683351153393 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2624400, while the sum is 50.
The spelling of 683351153393 in words is "six hundred eighty-three billion, three hundred fifty-one million, one hundred fifty-three thousand, three hundred ninety-three".
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