Base | Representation |
---|---|
bin | 1100101111011001… |
… | …11101100110011001 |
3 | 122122200212202211022 |
4 | 12113230331212121 |
5 | 103002032113221 |
6 | 3050423212225 |
7 | 331335002021 |
oct | 62754754631 |
9 | 18580782738 |
10 | 6840113561 |
11 | 29a007a616 |
12 | 13aa8a7075 |
13 | 850155098 |
14 | 48c61aa81 |
15 | 2a07854ab |
hex | 197b3d999 |
6840113561 has 2 divisors, whose sum is σ = 6840113562. Its totient is φ = 6840113560.
The previous prime is 6840113551. The next prime is 6840113573. The reversal of 6840113561 is 1653110486.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6375064336 + 465049225 = 79844^2 + 21565^2 .
It is a cyclic number.
It is not a de Polignac number, because 6840113561 - 214 = 6840097177 is a prime.
It is a super-2 number, since 2×68401135612 = 93574307054752201442, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (6840113551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3420056780 + 3420056781.
It is an arithmetic number, because the mean of its divisors is an integer number (3420056781).
Almost surely, 26840113561 is an apocalyptic number.
It is an amenable number.
6840113561 is a deficient number, since it is larger than the sum of its proper divisors (1).
6840113561 is an equidigital number, since it uses as much as digits as its factorization.
6840113561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 35.
The square root of 6840113561 is about 82704.9790580954. The cubic root of 6840113561 is about 1898.2544967371.
The spelling of 6840113561 in words is "six billion, eight hundred forty million, one hundred thirteen thousand, five hundred sixty-one".
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