Base | Representation |
---|---|
bin | 11111001011010001101000… |
… | …01111011001011010011001 |
3 | 22222201222222021022110112001 |
4 | 33211220310033121122121 |
5 | 32441220012433231413 |
6 | 401450414541121001 |
7 | 20304042643450624 |
oct | 1745506417313231 |
9 | 288658867273461 |
10 | 68557144430233 |
11 | 1a931a15827a88 |
12 | 7832a00b59161 |
13 | 2c33bac564a34 |
14 | 12d027d720dbb |
15 | 7dd4de3394dd |
hex | 3e5a343d9699 |
68557144430233 has 2 divisors, whose sum is σ = 68557144430234. Its totient is φ = 68557144430232.
The previous prime is 68557144430153. The next prime is 68557144430261. The reversal of 68557144430233 is 33203444175586.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44290515732544 + 24266628697689 = 6655112^2 + 4926117^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-68557144430233 is a prime.
It is not a weakly prime, because it can be changed into another prime (68557144430293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34278572215116 + 34278572215117.
It is an arithmetic number, because the mean of its divisors is an integer number (34278572215117).
Almost surely, 268557144430233 is an apocalyptic number.
It is an amenable number.
68557144430233 is a deficient number, since it is larger than the sum of its proper divisors (1).
68557144430233 is an equidigital number, since it uses as much as digits as its factorization.
68557144430233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 29030400, while the sum is 55.
The spelling of 68557144430233 in words is "sixty-eight trillion, five hundred fifty-seven billion, one hundred forty-four million, four hundred thirty thousand, two hundred thirty-three".
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