Base | Representation |
---|---|
bin | 100000010010111110… |
… | …0001001010011011001 |
3 | 20122000112112212121021 |
4 | 1000211330021103121 |
5 | 2114020114003343 |
6 | 51510043442441 |
7 | 5003464164004 |
oct | 1004574112331 |
9 | 218015485537 |
10 | 69356000473 |
11 | 27460721761 |
12 | 11537226421 |
13 | 6703bb4946 |
14 | 34dd29853b |
15 | 1c0dd010ed |
hex | 1025f094d9 |
69356000473 has 2 divisors, whose sum is σ = 69356000474. Its totient is φ = 69356000472.
The previous prime is 69356000459. The next prime is 69356000491. The reversal of 69356000473 is 37400065396.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 59035878729 + 10320121744 = 242973^2 + 101588^2 .
It is a cyclic number.
It is not a de Polignac number, because 69356000473 - 29 = 69355999961 is a prime.
It is a super-2 number, since 2×693560004732 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (69356000423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 34678000236 + 34678000237.
It is an arithmetic number, because the mean of its divisors is an integer number (34678000237).
Almost surely, 269356000473 is an apocalyptic number.
It is an amenable number.
69356000473 is a deficient number, since it is larger than the sum of its proper divisors (1).
69356000473 is an equidigital number, since it uses as much as digits as its factorization.
69356000473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 408240, while the sum is 43.
The spelling of 69356000473 in words is "sixty-nine billion, three hundred fifty-six million, four hundred seventy-three", and thus it is an aban number.
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