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6944381319433 is a prime number
BaseRepresentation
bin110010100001101110101…
…1000011011100100001001
3220120212122212121021000011
41211003131120123210021
51402234043104210213
622434112120111521
71314500146165435
oct145033530334411
926525585537004
106944381319433
112238106240438
12941a4b3055a1
133b4b107c075c
141a01775d79c5
15c098c94503d
hex650dd61b909

6944381319433 has 2 divisors, whose sum is σ = 6944381319434. Its totient is φ = 6944381319432.

The previous prime is 6944381319377. The next prime is 6944381319509. The reversal of 6944381319433 is 3349131834496.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5316838153929 + 1627543165504 = 2305827^2 + 1275752^2 .

It is a cyclic number.

It is not a de Polignac number, because 6944381319433 - 217 = 6944381188361 is a prime.

It is not a weakly prime, because it can be changed into another prime (6944381311433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3472190659716 + 3472190659717.

It is an arithmetic number, because the mean of its divisors is an integer number (3472190659717).

Almost surely, 26944381319433 is an apocalyptic number.

It is an amenable number.

6944381319433 is a deficient number, since it is larger than the sum of its proper divisors (1).

6944381319433 is an equidigital number, since it uses as much as digits as its factorization.

6944381319433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 20155392, while the sum is 58.

The spelling of 6944381319433 in words is "six trillion, nine hundred forty-four billion, three hundred eighty-one million, three hundred nineteen thousand, four hundred thirty-three".