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70547119441 is a prime number
BaseRepresentation
bin100000110110011101…
…1111001110101010001
320202002112211222122121
41001230323321311101
52123440030310231
652224153334241
75045136423031
oct1015473716521
9222075758577
1070547119441
1127a12011aa7
121180a107381
1368638b9976
1435b35558c1
151c7d685311
hex106cef9d51

70547119441 has 2 divisors, whose sum is σ = 70547119442. Its totient is φ = 70547119440.

The previous prime is 70547119397. The next prime is 70547119457. The reversal of 70547119441 is 14491174507.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69447533841 + 1099585600 = 263529^2 + 33160^2 .

It is an emirp because it is prime and its reverse (14491174507) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 70547119441 - 231 = 68399635793 is a prime.

It is a super-3 number, since 3×705471194413 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (70547119241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35273559720 + 35273559721.

It is an arithmetic number, because the mean of its divisors is an integer number (35273559721).

Almost surely, 270547119441 is an apocalyptic number.

It is an amenable number.

70547119441 is a deficient number, since it is larger than the sum of its proper divisors (1).

70547119441 is an equidigital number, since it uses as much as digits as its factorization.

70547119441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141120, while the sum is 43.

The spelling of 70547119441 in words is "seventy billion, five hundred forty-seven million, one hundred nineteen thousand, four hundred forty-one".