Base | Representation |
---|---|
bin | 100001000011101100… |
… | …1111110101110101001 |
3 | 20210020111111012100011 |
4 | 1002013121332232221 |
5 | 2130342222231213 |
6 | 52340220011521 |
7 | 5062141224622 |
oct | 1020731765651 |
9 | 223214435304 |
10 | 70991211433 |
11 | 2811a76297a |
12 | 11912990ba1 |
13 | 69048c84ac |
14 | 3616516a49 |
15 | 1ca765803d |
hex | 108767eba9 |
70991211433 has 2 divisors, whose sum is σ = 70991211434. Its totient is φ = 70991211432.
The previous prime is 70991211427. The next prime is 70991211457. The reversal of 70991211433 is 33411219907.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 70770896784 + 220314649 = 266028^2 + 14843^2 .
It is a cyclic number.
It is not a de Polignac number, because 70991211433 - 29 = 70991210921 is a prime.
It is a super-3 number, since 3×709912114333 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (70991211493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35495605716 + 35495605717.
It is an arithmetic number, because the mean of its divisors is an integer number (35495605717).
Almost surely, 270991211433 is an apocalyptic number.
It is an amenable number.
70991211433 is a deficient number, since it is larger than the sum of its proper divisors (1).
70991211433 is an equidigital number, since it uses as much as digits as its factorization.
70991211433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 40.
The spelling of 70991211433 in words is "seventy billion, nine hundred ninety-one million, two hundred eleven thousand, four hundred thirty-three".
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