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71108849113 is a prime number
BaseRepresentation
bin100001000111001101…
…0101110110111011001
320210112200211210220021
41002032122232313121
52131112331132423
652400021230441
75065100146621
oct1021632566731
9223480753807
1071108849113
11281801008a5
1211946262421
1369230a60a3
143627db9881
151cb2b4395d
hex108e6aedd9

71108849113 has 2 divisors, whose sum is σ = 71108849114. Its totient is φ = 71108849112.

The previous prime is 71108849101. The next prime is 71108849131. The reversal of 71108849113 is 31194880117.

Together with next prime (71108849131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69104317129 + 2004531984 = 262877^2 + 44772^2 .

It is a cyclic number.

It is not a de Polignac number, because 71108849113 - 213 = 71108840921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 71108849113.

It is not a weakly prime, because it can be changed into another prime (71108849213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35554424556 + 35554424557.

It is an arithmetic number, because the mean of its divisors is an integer number (35554424557).

Almost surely, 271108849113 is an apocalyptic number.

It is an amenable number.

71108849113 is a deficient number, since it is larger than the sum of its proper divisors (1).

71108849113 is an equidigital number, since it uses as much as digits as its factorization.

71108849113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48384, while the sum is 43.

The spelling of 71108849113 in words is "seventy-one billion, one hundred eight million, eight hundred forty-nine thousand, one hundred thirteen".