Base | Representation |
---|---|
bin | 10000001011100001011000… |
… | …101010101110011011000011 |
3 | 100022221212200222221101011111 |
4 | 100023201120222232123003 |
5 | 33311343203433132311 |
6 | 411202403545224151 |
7 | 20663114445552436 |
oct | 2013413052563303 |
9 | 308855628841144 |
10 | 71160505755331 |
11 | 20746001391693 |
12 | 7b93471492057 |
13 | 3092539c5aa65 |
14 | 1380288a3581d |
15 | 8360ac2ecd21 |
hex | 40b858aae6c3 |
71160505755331 has 2 divisors, whose sum is σ = 71160505755332. Its totient is φ = 71160505755330.
The previous prime is 71160505755281. The next prime is 71160505755341. The reversal of 71160505755331 is 13355750506117.
It is a strong prime.
It is an emirp because it is prime and its reverse (13355750506117) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 71160505755331 - 217 = 71160505624259 is a prime.
It is a super-2 number, since 2×711605057553312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (71160505755341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35580252877665 + 35580252877666.
It is an arithmetic number, because the mean of its divisors is an integer number (35580252877666).
Almost surely, 271160505755331 is an apocalyptic number.
71160505755331 is a deficient number, since it is larger than the sum of its proper divisors (1).
71160505755331 is an equidigital number, since it uses as much as digits as its factorization.
71160505755331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1653750, while the sum is 49.
The spelling of 71160505755331 in words is "seventy-one trillion, one hundred sixty billion, five hundred five million, seven hundred fifty-five thousand, three hundred thirty-one".
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