Base | Representation |
---|---|
bin | 1000011111001… |
… | …10110010101001 |
3 | 11221222022220211 |
4 | 10033212302221 |
5 | 121211344123 |
6 | 11022021121 |
7 | 1523121631 |
oct | 417466251 |
9 | 157868824 |
10 | 71199913 |
11 | 37210604 |
12 | 1ba177a1 |
13 | 1199ba35 |
14 | 96556c1 |
15 | 63b640d |
hex | 43e6ca9 |
71199913 has 2 divisors, whose sum is σ = 71199914. Its totient is φ = 71199912.
The previous prime is 71199899. The next prime is 71199917. The reversal of 71199913 is 31999117.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 63872064 + 7327849 = 7992^2 + 2707^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-71199913 is a prime.
It is a super-3 number, since 3×711999133 (a number of 25 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (71199917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35599956 + 35599957.
It is an arithmetic number, because the mean of its divisors is an integer number (35599957).
Almost surely, 271199913 is an apocalyptic number.
It is an amenable number.
71199913 is a deficient number, since it is larger than the sum of its proper divisors (1).
71199913 is an equidigital number, since it uses as much as digits as its factorization.
71199913 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15309, while the sum is 40.
The square root of 71199913 is about 8438.0040886456. The cubic root of 71199913 is about 414.4700507967.
The spelling of 71199913 in words is "seventy-one million, one hundred ninety-nine thousand, nine hundred thirteen".
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