7130041622113 has 2 divisors, whose sum is σ = 7130041622114. Its totient is φ = 7130041622112.

The previous prime is 7130041622083. The next prime is 7130041622131. The reversal of 7130041622113 is 3112261400317.

Together with next prime (7130041622131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4107687188049 + 3022354434064 = 2026743^2 + 1738492^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-7130041622113 is a prime.

It is not a weakly prime, because it can be changed into another prime (7130041622153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3565020811056 + 3565020811057.

It is an arithmetic number, because the mean of its divisors is an integer number (3565020811057).

Almost surely, 2^{7130041622113} is an apocalyptic number.

It is an amenable number.

7130041622113 is a deficient number, since it is larger than the sum of its proper divisors (1).

7130041622113 is an equidigital number, since it uses as much as digits as its factorization.

7130041622113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

The spelling of 7130041622113 in words is "seven trillion, one hundred thirty billion, forty-one million, six hundred twenty-two thousand, one hundred thirteen".