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71335134121 is a prime number
BaseRepresentation
bin100001001101111100…
…1111100001110101001
320211010110122021120111
41002123321330032221
52132043243242441
652434303254321
75103515430646
oct1023371741651
9224113567514
1071335134121
11282869070a9
12119a9baa3a1
13695ac34444
14364a080dcd
151cc7941081
hex109be7c3a9

71335134121 has 2 divisors, whose sum is σ = 71335134122. Its totient is φ = 71335134120.

The previous prime is 71335134109. The next prime is 71335134139. The reversal of 71335134121 is 12143153317.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 55316688025 + 16018446096 = 235195^2 + 126564^2 .

It is an emirp because it is prime and its reverse (12143153317) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 71335134121 - 27 = 71335133993 is a prime.

It is a super-2 number, since 2×713351341212 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (71335134181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35667567060 + 35667567061.

It is an arithmetic number, because the mean of its divisors is an integer number (35667567061).

Almost surely, 271335134121 is an apocalyptic number.

It is an amenable number.

71335134121 is a deficient number, since it is larger than the sum of its proper divisors (1).

71335134121 is an equidigital number, since it uses as much as digits as its factorization.

71335134121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7560, while the sum is 31.

Adding to 71335134121 its reverse (12143153317), we get a palindrome (83478287438).

The spelling of 71335134121 in words is "seventy-one billion, three hundred thirty-five million, one hundred thirty-four thousand, one hundred twenty-one".