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713584583953 is a prime number
BaseRepresentation
bin10100110001001001111…
…01001010010100010001
32112012212221021202121221
422120210331022110101
543142410123141303
61303452150045041
7102361201612363
oct12304475122421
92465787252557
10713584583953
112556a199268a
12b636a049781
13523a199a6b7
1426775562d33
15138669ce4bd
hexa624f4a511

713584583953 has 2 divisors, whose sum is σ = 713584583954. Its totient is φ = 713584583952.

The previous prime is 713584583923. The next prime is 713584583963. The reversal of 713584583953 is 359385485317.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 527623546129 + 185961037824 = 726377^2 + 431232^2 .

It is a cyclic number.

It is not a de Polignac number, because 713584583953 - 217 = 713584452881 is a prime.

It is a super-2 number, since 2×7135845839532 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 713584583891 and 713584583900.

It is not a weakly prime, because it can be changed into another prime (713584583923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 356792291976 + 356792291977.

It is an arithmetic number, because the mean of its divisors is an integer number (356792291977).

Almost surely, 2713584583953 is an apocalyptic number.

It is an amenable number.

713584583953 is a deficient number, since it is larger than the sum of its proper divisors (1).

713584583953 is an equidigital number, since it uses as much as digits as its factorization.

713584583953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54432000, while the sum is 61.

The spelling of 713584583953 in words is "seven hundred thirteen billion, five hundred eighty-four million, five hundred eighty-three thousand, nine hundred fifty-three".