Base | Representation |
---|---|
bin | 110011111100000100000… |
… | …0111000001011001001001 |
3 | 221021102101101201212110202 |
4 | 1213320020013001121021 |
5 | 1413423341124020033 |
6 | 23103153411221545 |
7 | 1334505335230046 |
oct | 147701007013111 |
9 | 27242341655422 |
10 | 7138371704393 |
11 | 2302403803936 |
12 | 97356a2a78b5 |
13 | 3ca1b7a585a7 |
14 | 1a96db4c61cd |
15 | c5a434d28e8 |
hex | 67e081c1649 |
7138371704393 has 2 divisors, whose sum is σ = 7138371704394. Its totient is φ = 7138371704392.
The previous prime is 7138371704357. The next prime is 7138371704437. The reversal of 7138371704393 is 3934071738317.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3900340605184 + 3238031099209 = 1974928^2 + 1799453^2 .
It is a cyclic number.
It is not a de Polignac number, because 7138371704393 - 212 = 7138371700297 is a prime.
It is not a weakly prime, because it can be changed into another prime (7138371709393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3569185852196 + 3569185852197.
It is an arithmetic number, because the mean of its divisors is an integer number (3569185852197).
Almost surely, 27138371704393 is an apocalyptic number.
It is an amenable number.
7138371704393 is a deficient number, since it is larger than the sum of its proper divisors (1).
7138371704393 is an equidigital number, since it uses as much as digits as its factorization.
7138371704393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8001504, while the sum is 56.
The spelling of 7138371704393 in words is "seven trillion, one hundred thirty-eight billion, three hundred seventy-one million, seven hundred four thousand, three hundred ninety-three".
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