Base | Representation |
---|---|
bin | 10000001110110001110100… |
… | …000100111110101001101011 |
3 | 100100202021100212200011202202 |
4 | 100032301310010332221223 |
5 | 33324030023300444041 |
6 | 411453255124450415 |
7 | 21015226411565051 |
oct | 2016616404765153 |
9 | 310667325604682 |
10 | 71384303921771 |
11 | 20821a05640535 |
12 | 800a90ab49a0b |
13 | 30aa6847c9509 |
14 | 138b0396141d1 |
15 | 83bd09b95a9b |
hex | 40ec7413ea6b |
71384303921771 has 2 divisors, whose sum is σ = 71384303921772. Its totient is φ = 71384303921770.
The previous prime is 71384303921761. The next prime is 71384303921809. The reversal of 71384303921771 is 17712930348317.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-71384303921771 is a prime.
It is a super-3 number, since 3×713843039217713 (a number of 43 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (71384303921741) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35692151960885 + 35692151960886.
It is an arithmetic number, because the mean of its divisors is an integer number (35692151960886).
Almost surely, 271384303921771 is an apocalyptic number.
71384303921771 is a deficient number, since it is larger than the sum of its proper divisors (1).
71384303921771 is an equidigital number, since it uses as much as digits as its factorization.
71384303921771 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5334336, while the sum is 56.
The spelling of 71384303921771 in words is "seventy-one trillion, three hundred eighty-four billion, three hundred three million, nine hundred twenty-one thousand, seven hundred seventy-one".
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