Base | Representation |
---|---|
bin | 100001010001011100… |
… | …1011010000000110001 |
3 | 20211102122100202102021 |
4 | 1002202321122000301 |
5 | 2132313310400411 |
6 | 52454053351441 |
7 | 5106441446341 |
oct | 1024271320061 |
9 | 224378322367 |
10 | 71452434481 |
11 | 2833704464a |
12 | 11a21338581 |
13 | 697932463c |
14 | 365b896d21 |
15 | 1cd2db1a71 |
hex | 10a2e5a031 |
71452434481 has 2 divisors, whose sum is σ = 71452434482. Its totient is φ = 71452434480.
The previous prime is 71452434439. The next prime is 71452434503. The reversal of 71452434481 is 18443425417.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68447640625 + 3004793856 = 261625^2 + 54816^2 .
It is a cyclic number.
It is not a de Polignac number, because 71452434481 - 27 = 71452434353 is a prime.
It is a super-2 number, since 2×714524344812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (71452432481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35726217240 + 35726217241.
It is an arithmetic number, because the mean of its divisors is an integer number (35726217241).
Almost surely, 271452434481 is an apocalyptic number.
It is an amenable number.
71452434481 is a deficient number, since it is larger than the sum of its proper divisors (1).
71452434481 is an equidigital number, since it uses as much as digits as its factorization.
71452434481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 430080, while the sum is 43.
Adding to 71452434481 its reverse (18443425417), we get a palindrome (89895859898).
The spelling of 71452434481 in words is "seventy-one billion, four hundred fifty-two million, four hundred thirty-four thousand, four hundred eighty-one".
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