Base | Representation |
---|---|
bin | 10000011111010110011100… |
… | …100111001010011101100001 |
3 | 100111210010221001001200110101 |
4 | 100133112130213022131201 |
5 | 34001204402434230441 |
6 | 414124401511102401 |
7 | 21163424162250415 |
oct | 2037263447123541 |
9 | 314703831050411 |
10 | 72523150305121 |
11 | 2112099374427a |
12 | 8173580371a01 |
13 | 3160b99652a29 |
14 | 13ca1d3d90d45 |
15 | 85b760c06231 |
hex | 41f59c9ca761 |
72523150305121 has 2 divisors, whose sum is σ = 72523150305122. Its totient is φ = 72523150305120.
The previous prime is 72523150305079. The next prime is 72523150305139. The reversal of 72523150305121 is 12150305132527.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 51447108856896 + 21076041448225 = 7172664^2 + 4590865^2 .
It is a cyclic number.
It is not a de Polignac number, because 72523150305121 - 221 = 72523148207969 is a prime.
It is not a weakly prime, because it can be changed into another prime (72523150305421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36261575152560 + 36261575152561.
It is an arithmetic number, because the mean of its divisors is an integer number (36261575152561).
Almost surely, 272523150305121 is an apocalyptic number.
It is an amenable number.
72523150305121 is a deficient number, since it is larger than the sum of its proper divisors (1).
72523150305121 is an equidigital number, since it uses as much as digits as its factorization.
72523150305121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 63000, while the sum is 37.
Adding to 72523150305121 its reverse (12150305132527), we get a palindrome (84673455437648).
The spelling of 72523150305121 in words is "seventy-two trillion, five hundred twenty-three billion, one hundred fifty million, three hundred five thousand, one hundred twenty-one".
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