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73055537 is a prime number
BaseRepresentation
bin1000101101010…
…11110100110001
312002110121100122
410112223310301
5122200234122
611125500025
71544650622
oct426536461
9162417318
1073055537
1138268785
1220571615
131219b539
1499b9a49
156631142
hex45abd31

73055537 has 2 divisors, whose sum is σ = 73055538. Its totient is φ = 73055536.

The previous prime is 73055533. The next prime is 73055569. The reversal of 73055537 is 73555037.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 69872881 + 3182656 = 8359^2 + 1784^2 .

It is a cyclic number.

It is not a de Polignac number, because 73055537 - 22 = 73055533 is a prime.

It is a super-2 number, since 2×730555372 = 10674222972716738, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 73055497 and 73055506.

It is not a weakly prime, because it can be changed into another prime (73055533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36527768 + 36527769.

It is an arithmetic number, because the mean of its divisors is an integer number (36527769).

Almost surely, 273055537 is an apocalyptic number.

It is an amenable number.

73055537 is a deficient number, since it is larger than the sum of its proper divisors (1).

73055537 is an equidigital number, since it uses as much as digits as its factorization.

73055537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 55125, while the sum is 35.

The square root of 73055537 is about 8547.2531845032. The cubic root of 73055537 is about 418.0398781426.

Subtracting 73055537 from its reverse (73555037), we obtain a triangular number (499500 = T999).

The spelling of 73055537 in words is "seventy-three million, fifty-five thousand, five hundred thirty-seven".