Base | Representation |
---|---|
bin | 100010001100101011… |
… | …1010111101100011001 |
3 | 21000120011022120211101 |
4 | 1010121113113230121 |
5 | 2200401120011133 |
6 | 53423214031401 |
7 | 5206624464325 |
oct | 1043127275431 |
9 | 230504276741 |
10 | 73440000793 |
11 | 29166a69635 |
12 | 12296aa8561 |
13 | 6c05037493 |
14 | 37a9836985 |
15 | 1d9c61a37d |
hex | 11195d7b19 |
73440000793 has 2 divisors, whose sum is σ = 73440000794. Its totient is φ = 73440000792.
The previous prime is 73440000709. The next prime is 73440000797. The reversal of 73440000793 is 39700004437.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 45408200464 + 28031800329 = 213092^2 + 167427^2 .
It is an emirp because it is prime and its reverse (39700004437) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 73440000793 - 213 = 73439992601 is a prime.
It is not a weakly prime, because it can be changed into another prime (73440000797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36720000396 + 36720000397.
It is an arithmetic number, because the mean of its divisors is an integer number (36720000397).
Almost surely, 273440000793 is an apocalyptic number.
It is an amenable number.
73440000793 is a deficient number, since it is larger than the sum of its proper divisors (1).
73440000793 is an equidigital number, since it uses as much as digits as its factorization.
73440000793 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 63504, while the sum is 37.
The spelling of 73440000793 in words is "seventy-three billion, four hundred forty million, seven hundred ninety-three", and thus it is an aban number.
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