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73523543332051 is a prime number
BaseRepresentation
bin10000101101111010001000…
…101011101101010011010011
3100122022210010011000221112101
4100231322020223231103103
534114102204043111201
6420212125521341231
721325620641546521
oct2055721053552323
9318283104027471
1073523543332051
112147718350210a
1282b5431a97817
13320431818ac87
1414227b66a5311
158777b1c04d01
hex42de88aed4d3

73523543332051 has 2 divisors, whose sum is σ = 73523543332052. Its totient is φ = 73523543332050.

The previous prime is 73523543332027. The next prime is 73523543332103. The reversal of 73523543332051 is 15023334532537.

It is a weak prime.

It is an emirp because it is prime and its reverse (15023334532537) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 73523543332051 - 27 = 73523543331923 is a prime.

It is a super-2 number, since 2×735235433320512 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 73523543331992 and 73523543332010.

It is not a weakly prime, because it can be changed into another prime (73523543332021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 36761771666025 + 36761771666026.

It is an arithmetic number, because the mean of its divisors is an integer number (36761771666026).

Almost surely, 273523543332051 is an apocalyptic number.

73523543332051 is a deficient number, since it is larger than the sum of its proper divisors (1).

73523543332051 is an equidigital number, since it uses as much as digits as its factorization.

73523543332051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402000, while the sum is 46.

Adding to 73523543332051 its reverse (15023334532537), we get a palindrome (88546877864588).

The spelling of 73523543332051 in words is "seventy-three trillion, five hundred twenty-three billion, five hundred forty-three million, three hundred thirty-two thousand, fifty-one".