Base | Representation |
---|---|
bin | 10000110101000010111010… |
… | …100000111001101111010001 |
3 | 100201001200002022101021220010 |
4 | 100311002322200321233101 |
5 | 34200121140420210303 |
6 | 421225321554505133 |
7 | 21406223025402312 |
oct | 2065027240715721 |
9 | 321050068337803 |
10 | 74014005631953 |
11 | 21646188702332 |
12 | 83744b08951a9 |
13 | 323b64c33390a |
14 | 143c422d06609 |
15 | 88541a347c03 |
hex | 4350ba839bd1 |
74014005631953 has 32 divisors (see below), whose sum is σ = 105024327632640. Its totient is φ = 46288499362560.
The previous prime is 74014005631897. The next prime is 74014005631961. The reversal of 74014005631953 is 35913650041047.
It is not a de Polignac number, because 74014005631953 - 236 = 73945286155217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (74014005681953) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 77445538 + ... + 78395403.
It is an arithmetic number, because the mean of its divisors is an integer number (3282010238520).
Almost surely, 274014005631953 is an apocalyptic number.
It is an amenable number.
74014005631953 is a deficient number, since it is larger than the sum of its proper divisors (31010322000687).
74014005631953 is a wasteful number, since it uses less digits than its factorization.
74014005631953 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155841129.
The product of its (nonzero) digits is 1360800, while the sum is 48.
The spelling of 74014005631953 in words is "seventy-four trillion, fourteen billion, five million, six hundred thirty-one thousand, nine hundred fifty-three".
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