Base | Representation |
---|---|
bin | 100010011110011000… |
… | …0101100011001110101 |
3 | 21002002112201211112001 |
4 | 1010330300230121311 |
5 | 2203110130414111 |
6 | 54002150055301 |
7 | 5230425162214 |
oct | 1047460543165 |
9 | 232075654461 |
10 | 74033841781 |
11 | 294411a0109 |
12 | 1242194a531 |
13 | 6c9b087893 |
14 | 382465907b |
15 | 1dd481d1c1 |
hex | 113cc2c675 |
74033841781 has 4 divisors (see below), whose sum is σ = 75609029952. Its totient is φ = 72458653612.
The previous prime is 74033841779. The next prime is 74033841803. The reversal of 74033841781 is 18714833047.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 74033841781 - 21 = 74033841779 is a prime.
It is a super-2 number, since 2×740338417812 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (74033841701) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 787594015 + ... + 787594108.
It is an arithmetic number, because the mean of its divisors is an integer number (18902257488).
Almost surely, 274033841781 is an apocalyptic number.
It is an amenable number.
74033841781 is a deficient number, since it is larger than the sum of its proper divisors (1575188171).
74033841781 is a wasteful number, since it uses less digits than its factorization.
74033841781 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1575188170.
The product of its (nonzero) digits is 451584, while the sum is 46.
The spelling of 74033841781 in words is "seventy-four billion, thirty-three million, eight hundred forty-one thousand, seven hundred eighty-one".
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