Base | Representation |
---|---|
bin | 100010100011101110… |
… | …0100100110111011001 |
3 | 21002120001001222102211 |
4 | 1011013130210313121 |
5 | 2203442024224101 |
6 | 54032032355121 |
7 | 5235033042523 |
oct | 1050734446731 |
9 | 232501058384 |
10 | 74213117401 |
11 | 29523408585 |
12 | 124719a5aa1 |
13 | 6cc9266b27 |
14 | 38403a4a13 |
15 | 1de5431c51 |
hex | 1147724dd9 |
74213117401 has 2 divisors, whose sum is σ = 74213117402. Its totient is φ = 74213117400.
The previous prime is 74213117389. The next prime is 74213117477. The reversal of 74213117401 is 10471131247.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 60761757001 + 13451360400 = 246499^2 + 115980^2 .
It is a cyclic number.
It is not a de Polignac number, because 74213117401 - 27 = 74213117273 is a prime.
It is not a weakly prime, because it can be changed into another prime (74213117701) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37106558700 + 37106558701.
It is an arithmetic number, because the mean of its divisors is an integer number (37106558701).
Almost surely, 274213117401 is an apocalyptic number.
It is an amenable number.
74213117401 is a deficient number, since it is larger than the sum of its proper divisors (1).
74213117401 is an equidigital number, since it uses as much as digits as its factorization.
74213117401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4704, while the sum is 31.
Adding to 74213117401 its reverse (10471131247), we get a palindrome (84684248648).
The spelling of 74213117401 in words is "seventy-four billion, two hundred thirteen million, one hundred seventeen thousand, four hundred one".
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