Base | Representation |
---|---|
bin | 10101110100110100100… |
… | …11001001011011010001 |
3 | 2122200122201122112101111 |
4 | 22322122103021123101 |
5 | 44241310213120423 |
6 | 1332301050333321 |
7 | 105115354332415 |
oct | 12723223113321 |
9 | 2580581575344 |
10 | 749913020113 |
11 | 26a044393444 |
12 | 10140842a241 |
13 | 559411a457a |
14 | 28420272d45 |
15 | 14790eba60d |
hex | ae9a4c96d1 |
749913020113 has 2 divisors, whose sum is σ = 749913020114. Its totient is φ = 749913020112.
The previous prime is 749913020093. The next prime is 749913020167. The reversal of 749913020113 is 311020319947.
749913020113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 590673713809 + 159239306304 = 768553^2 + 399048^2 .
It is a cyclic number.
It is not a de Polignac number, because 749913020113 - 29 = 749913019601 is a prime.
It is not a weakly prime, because it can be changed into another prime (749913027113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 374956510056 + 374956510057.
It is an arithmetic number, because the mean of its divisors is an integer number (374956510057).
Almost surely, 2749913020113 is an apocalyptic number.
It is an amenable number.
749913020113 is a deficient number, since it is larger than the sum of its proper divisors (1).
749913020113 is an equidigital number, since it uses as much as digits as its factorization.
749913020113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40824, while the sum is 40.
The spelling of 749913020113 in words is "seven hundred forty-nine billion, nine hundred thirteen million, twenty thousand, one hundred thirteen".
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