Base | Representation |
---|---|
bin | 100011000010011001… |
… | …0110000010000011011 |
3 | 21012012202201222100022 |
4 | 1012010302300100123 |
5 | 2213044014411103 |
6 | 54322120301055 |
7 | 5302401230555 |
oct | 1060462602033 |
9 | 235182658308 |
10 | 75242341403 |
11 | 29a01381829 |
12 | 126ba61178b |
13 | 7131566a08 |
14 | 38dad5c4d5 |
15 | 1e55987138 |
hex | 1184cb041b |
75242341403 has 2 divisors, whose sum is σ = 75242341404. Its totient is φ = 75242341402.
The previous prime is 75242341373. The next prime is 75242341429. The reversal of 75242341403 is 30414324257.
It is a strong prime.
It is an emirp because it is prime and its reverse (30414324257) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 75242341403 - 224 = 75225564187 is a prime.
It is a super-2 number, since 2×752423414032 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (75242341483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37621170701 + 37621170702.
It is an arithmetic number, because the mean of its divisors is an integer number (37621170702).
Almost surely, 275242341403 is an apocalyptic number.
75242341403 is a deficient number, since it is larger than the sum of its proper divisors (1).
75242341403 is an equidigital number, since it uses as much as digits as its factorization.
75242341403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 35.
The spelling of 75242341403 in words is "seventy-five billion, two hundred forty-two million, three hundred forty-one thousand, four hundred three".
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