Base | Representation |
---|---|
bin | 10001001001101101101000… |
… | …010110010101000001111001 |
3 | 100220002110000100222210221012 |
4 | 101021231220112111001321 |
5 | 34341403331343202132 |
6 | 424234004330523305 |
7 | 21613642213412162 |
oct | 2111555026250171 |
9 | 326073010883835 |
10 | 75434261303417 |
11 | 22043543a36375 |
12 | 85637b9596535 |
13 | 33125605923b3 |
14 | 148b07574c769 |
15 | 8ac3418c80b2 |
hex | 449b68595079 |
75434261303417 has 2 divisors, whose sum is σ = 75434261303418. Its totient is φ = 75434261303416.
The previous prime is 75434261303377. The next prime is 75434261303449. The reversal of 75434261303417 is 71430316243457.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 64033988511376 + 11400272792041 = 8002124^2 + 3376429^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-75434261303417 is a prime.
It is not a weakly prime, because it can be changed into another prime (75434261203417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 37717130651708 + 37717130651709.
It is an arithmetic number, because the mean of its divisors is an integer number (37717130651709).
Almost surely, 275434261303417 is an apocalyptic number.
It is an amenable number.
75434261303417 is a deficient number, since it is larger than the sum of its proper divisors (1).
75434261303417 is an equidigital number, since it uses as much as digits as its factorization.
75434261303417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5080320, while the sum is 50.
The spelling of 75434261303417 in words is "seventy-five trillion, four hundred thirty-four billion, two hundred sixty-one million, three hundred three thousand, four hundred seventeen".
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