Base | Representation |
---|---|
bin | 10001010101100001000010… |
… | …101000100000100100011011 |
3 | 100222221222122102221102122101 |
4 | 101111201002220200210123 |
5 | 34443201013100312021 |
6 | 430054350502504231 |
7 | 22026355346162035 |
oct | 2125410250404433 |
9 | 328858572842571 |
10 | 76245377354011 |
11 | 22326534892438 |
12 | 8674a46735077 |
13 | 3370ba65097a8 |
14 | 14b8420152c55 |
15 | 8c34b5a2ea91 |
hex | 455842a2091b |
76245377354011 has 2 divisors, whose sum is σ = 76245377354012. Its totient is φ = 76245377354010.
The previous prime is 76245377353979. The next prime is 76245377354023. The reversal of 76245377354011 is 11045377354267.
It is a strong prime.
It is an emirp because it is prime and its reverse (11045377354267) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 76245377354011 - 25 = 76245377353979 is a prime.
It is not a weakly prime, because it can be changed into another prime (76245377354611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38122688677005 + 38122688677006.
It is an arithmetic number, because the mean of its divisors is an integer number (38122688677006).
Almost surely, 276245377354011 is an apocalyptic number.
76245377354011 is a deficient number, since it is larger than the sum of its proper divisors (1).
76245377354011 is an equidigital number, since it uses as much as digits as its factorization.
76245377354011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14817600, while the sum is 55.
The spelling of 76245377354011 in words is "seventy-six trillion, two hundred forty-five billion, three hundred seventy-seven million, three hundred fifty-four thousand, eleven".
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