Base | Representation |
---|---|
bin | 100011100100111100… |
… | …0010011110010101111 |
3 | 21022012112202112221000 |
4 | 1013021320103302233 |
5 | 2222432231104313 |
6 | 55033123411343 |
7 | 5343204255000 |
oct | 1071170236257 |
9 | 238175675830 |
10 | 76401425583 |
11 | 2a44668193a |
12 | 12982823b53 |
13 | 7287733842 |
14 | 39aac7b1a7 |
15 | 1ec25de673 |
hex | 11c9e13caf |
76401425583 has 64 divisors (see below), whose sum is σ = 133806208000. Its totient is φ = 43059522240.
The previous prime is 76401425579. The next prime is 76401425621. The reversal of 76401425583 is 38552410467.
76401425583 is a `hidden beast` number, since 7 + 6 + 40 + 1 + 4 + 25 + 583 = 666.
It is not a de Polignac number, because 76401425583 - 22 = 76401425579 is a prime.
It is a super-2 number, since 2×764014255832 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (76401425983) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 619548 + ... + 732558.
It is an arithmetic number, because the mean of its divisors is an integer number (2090722000).
Almost surely, 276401425583 is an apocalyptic number.
76401425583 is a gapful number since it is divisible by the number (73) formed by its first and last digit.
76401425583 is a deficient number, since it is larger than the sum of its proper divisors (57404782417).
76401425583 is a wasteful number, since it uses less digits than its factorization.
76401425583 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 113114 (or 113094 counting only the distinct ones).
The product of its (nonzero) digits is 806400, while the sum is 45.
The spelling of 76401425583 in words is "seventy-six billion, four hundred one million, four hundred twenty-five thousand, five hundred eighty-three".
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