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765073531114001 is a prime number
BaseRepresentation
bin1010110111110101001001000…
…0000011001001001000010001
310201022220022111211110222000222
42231331102100003021020101
51300234431042431122001
611311101532245122425
7320102511214451054
oct25575222003111021
93638808454428028
10765073531114001
11201859953984a8a
12719844616b9415
1326ab9180451305
14d6cda83b12a9b
155d6b4b937861b
hex2b7d4900c9211

765073531114001 has 2 divisors, whose sum is σ = 765073531114002. Its totient is φ = 765073531114000.

The previous prime is 765073531113989. The next prime is 765073531114063. The reversal of 765073531114001 is 100411135370567.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 660274086248401 + 104799444865600 = 25695799^2 + 10237160^2 .

It is a cyclic number.

It is not a de Polignac number, because 765073531114001 - 230 = 765072457372177 is a prime.

It is a super-2 number, since 2×7650735311140012 (a number of 31 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (765073531144001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 382536765557000 + 382536765557001.

It is an arithmetic number, because the mean of its divisors is an integer number (382536765557001).

Almost surely, 2765073531114001 is an apocalyptic number.

It is an amenable number.

765073531114001 is a deficient number, since it is larger than the sum of its proper divisors (1).

765073531114001 is an equidigital number, since it uses as much as digits as its factorization.

765073531114001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 264600, while the sum is 44.

Adding to 765073531114001 its reverse (100411135370567), we get a palindrome (865484666484568).

The spelling of 765073531114001 in words is "seven hundred sixty-five trillion, seventy-three billion, five hundred thirty-one million, one hundred fourteen thousand, one".