Base | Representation |
---|---|
bin | 100011111010111101… |
… | …1011010000010100111 |
3 | 21101010001100010102021 |
4 | 1013311323122002213 |
5 | 2230440422410421 |
6 | 55234323124011 |
7 | 5400416610505 |
oct | 1076573320247 |
9 | 241101303367 |
10 | 77140435111 |
11 | 2a795845713 |
12 | 12b4a213607 |
13 | 737488099c |
14 | 3a3b08b675 |
15 | 201741a341 |
hex | 11f5eda0a7 |
77140435111 has 4 divisors (see below), whose sum is σ = 77142437224. Its totient is φ = 77138433000.
The previous prime is 77140434961. The next prime is 77140435121. The reversal of 77140435111 is 11153404177.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11153404177 = 90401 ⋅123377.
It is a cyclic number.
It is not a de Polignac number, because 77140435111 - 217 = 77140304039 is a prime.
It is a super-2 number, since 2×771404351112 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (77140435121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 942105 + ... + 1020706.
It is an arithmetic number, because the mean of its divisors is an integer number (19285609306).
Almost surely, 277140435111 is an apocalyptic number.
77140435111 is a deficient number, since it is larger than the sum of its proper divisors (2002113).
77140435111 is a wasteful number, since it uses less digits than its factorization.
77140435111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2002112.
The product of its (nonzero) digits is 11760, while the sum is 34.
Adding to 77140435111 its reverse (11153404177), we get a palindrome (88293839288).
The spelling of 77140435111 in words is "seventy-seven billion, one hundred forty million, four hundred thirty-five thousand, one hundred eleven".
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