Search a number
-
+
7825136953 is a prime number
BaseRepresentation
bin1110100100110101…
…00001110100111001
3202012100101010220011
413102122201310321
5112011213340303
63332251501521
7364625365234
oct72232416471
922170333804
107825136953
1133560a4237
1216247578a1
1397924a46a
1454338a41b
1530bea916d
hex1d26a1d39

7825136953 has 2 divisors, whose sum is σ = 7825136954. Its totient is φ = 7825136952.

The previous prime is 7825136939. The next prime is 7825137017. The reversal of 7825136953 is 3596315287.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7232311849 + 592825104 = 85043^2 + 24348^2 .

It is a cyclic number.

It is not a de Polignac number, because 7825136953 - 221 = 7823039801 is a prime.

It is a super-2 number, since 2×78251369532 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 7825136897 and 7825136906.

It is not a weakly prime, because it can be changed into another prime (7825131953) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3912568476 + 3912568477.

It is an arithmetic number, because the mean of its divisors is an integer number (3912568477).

Almost surely, 27825136953 is an apocalyptic number.

It is an amenable number.

7825136953 is a deficient number, since it is larger than the sum of its proper divisors (1).

7825136953 is an equidigital number, since it uses as much as digits as its factorization.

7825136953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1360800, while the sum is 49.

The square root of 7825136953 is about 88459.8041655079. The cubic root of 7825136953 is about 1985.3206006327.

The spelling of 7825136953 in words is "seven billion, eight hundred twenty-five million, one hundred thirty-six thousand, nine hundred fifty-three".