Base | Representation |
---|---|
bin | 100100110011101011… |
… | …0000000100101000001 |
3 | 21120000122210022221101 |
4 | 1021213112000211001 |
5 | 2243340031442423 |
6 | 100151214454401 |
7 | 5465523255454 |
oct | 1114726004501 |
9 | 246018708841 |
10 | 79043234113 |
11 | 30581932778 |
12 | 1339b504401 |
13 | 75b8b5455c |
14 | 3b7ba8349b |
15 | 20c94cc7ad |
hex | 1267580941 |
79043234113 has 2 divisors, whose sum is σ = 79043234114. Its totient is φ = 79043234112.
The previous prime is 79043234107. The next prime is 79043234141. The reversal of 79043234113 is 31143234097.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 78762738609 + 280495504 = 280647^2 + 16748^2 .
It is an emirp because it is prime and its reverse (31143234097) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-79043234113 is a prime.
It is not a weakly prime, because it can be changed into another prime (79043234173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39521617056 + 39521617057.
It is an arithmetic number, because the mean of its divisors is an integer number (39521617057).
Almost surely, 279043234113 is an apocalyptic number.
It is an amenable number.
79043234113 is a deficient number, since it is larger than the sum of its proper divisors (1).
79043234113 is an equidigital number, since it uses as much as digits as its factorization.
79043234113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 37.
The spelling of 79043234113 in words is "seventy-nine billion, forty-three million, two hundred thirty-four thousand, one hundred thirteen".
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