Base | Representation |
---|---|
bin | 100100111111010010… |
… | …0111110011100101001 |
3 | 21121000211021012012012 |
4 | 1021332210332130221 |
5 | 2300134324033023 |
6 | 100254021325305 |
7 | 5511265434041 |
oct | 1117644763451 |
9 | 247024235165 |
10 | 79433033513 |
11 | 30761970839 |
12 | 13489b66835 |
13 | 764b833ba2 |
14 | 3bb7750721 |
15 | 20ed828978 |
hex | 127e93e729 |
79433033513 has 2 divisors, whose sum is σ = 79433033514. Its totient is φ = 79433033512.
The previous prime is 79433033479. The next prime is 79433033527. The reversal of 79433033513 is 31533033497.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 50379149209 + 29053884304 = 224453^2 + 170452^2 .
It is a cyclic number.
It is not a de Polignac number, because 79433033513 - 28 = 79433033257 is a prime.
It is a super-2 number, since 2×794330335132 (a number of 23 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (79433036513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 39716516756 + 39716516757.
It is an arithmetic number, because the mean of its divisors is an integer number (39716516757).
Almost surely, 279433033513 is an apocalyptic number.
It is an amenable number.
79433033513 is a deficient number, since it is larger than the sum of its proper divisors (1).
79433033513 is an equidigital number, since it uses as much as digits as its factorization.
79433033513 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 306180, while the sum is 41.
The spelling of 79433033513 in words is "seventy-nine billion, four hundred thirty-three million, thirty-three thousand, five hundred thirteen".
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