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7949449513 is a prime number
BaseRepresentation
bin1110110011101001…
…01111100100101001
3202112000021212200001
413121310233210221
5112240024341023
63352452143001
7400665130435
oct73164574451
922460255601
107949449513
11340a291095
12165a307a61
13998c242a5
14555aa99c5
15317d626ad
hex1d9d2f929

7949449513 has 2 divisors, whose sum is σ = 7949449514. Its totient is φ = 7949449512.

The previous prime is 7949449493. The next prime is 7949449531. The reversal of 7949449513 is 3159449497.

Together with next prime (7949449531) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7948970649 + 478864 = 89157^2 + 692^2 .

It is an emirp because it is prime and its reverse (3159449497) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 7949449513 - 229 = 7412578601 is a prime.

It is not a weakly prime, because it can be changed into another prime (7949449553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3974724756 + 3974724757.

It is an arithmetic number, because the mean of its divisors is an integer number (3974724757).

Almost surely, 27949449513 is an apocalyptic number.

It is an amenable number.

7949449513 is a deficient number, since it is larger than the sum of its proper divisors (1).

7949449513 is an equidigital number, since it uses as much as digits as its factorization.

7949449513 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4898880, while the sum is 55.

The square root of 7949449513 is about 89159.6854693869. The cubic root of 7949449513 is about 1995.7785553884.

The spelling of 7949449513 in words is "seven billion, nine hundred forty-nine million, four hundred forty-nine thousand, five hundred thirteen".