Base | Representation |
---|---|
bin | 111010100000111101101… |
… | …0111000101101100100011 |
3 | 1001110211110010020221011212 |
4 | 1311001323113011230203 |
5 | 2023231011044201243 |
6 | 25034320302300335 |
7 | 1460014261506524 |
oct | 165017327055443 |
9 | 31424403227155 |
10 | 8042248428323 |
11 | 26207756387aa |
12 | a9a7848876ab |
13 | 4644c4732c85 |
14 | 1db3656d284b |
15 | de2e6033318 |
hex | 7507b5c5b23 |
8042248428323 has 2 divisors, whose sum is σ = 8042248428324. Its totient is φ = 8042248428322.
The previous prime is 8042248428317. The next prime is 8042248428359. The reversal of 8042248428323 is 3238248422408.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 8042248428323 - 26 = 8042248428259 is a prime.
It is a super-3 number, since 3×80422484283233 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (8042241428323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4021124214161 + 4021124214162.
It is an arithmetic number, because the mean of its divisors is an integer number (4021124214162).
Almost surely, 28042248428323 is an apocalyptic number.
8042248428323 is a deficient number, since it is larger than the sum of its proper divisors (1).
8042248428323 is an equidigital number, since it uses as much as digits as its factorization.
8042248428323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4718592, while the sum is 50.
The spelling of 8042248428323 in words is "eight trillion, forty-two billion, two hundred forty-eight million, four hundred twenty-eight thousand, three hundred twenty-three".
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