Base | Representation |
---|---|
bin | 1011011100000000110111011… |
… | …0011101000010101001000111 |
3 | 10220112202121120221000122011212 |
4 | 2313000031312131002221013 |
5 | 1320443240410220232112 |
6 | 11531442213325322035 |
7 | 331350012163363250 |
oct | 26700156635025107 |
9 | 3815677527018155 |
10 | 804857383758407 |
11 | 2134a81105a7681 |
12 | 7632a90540631b |
13 | 2871395825c315 |
14 | 102a743b77bb27 |
15 | 630b2c321e522 |
hex | 2dc0376742a47 |
804857383758407 has 32 divisors (see below), whose sum is σ = 982799751098880. Its totient is φ = 643812666940800.
The previous prime is 804857383758377. The next prime is 804857383758433. The reversal of 804857383758407 is 704857383758408.
It is not a de Polignac number, because 804857383758407 - 28 = 804857383758151 is a prime.
It is a super-2 number, since 2×8048573837584072 (a number of 31 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (804857383758457) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 149425853 + ... + 154718454.
It is an arithmetic number, because the mean of its divisors is an integer number (30712492221840).
Almost surely, 2804857383758407 is an apocalyptic number.
804857383758407 is a deficient number, since it is larger than the sum of its proper divisors (177942367340473).
804857383758407 is a wasteful number, since it uses less digits than its factorization.
804857383758407 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 304144631.
The product of its (nonzero) digits is 5057740800, while the sum is 77.
Subtracting from 804857383758407 its reverse (704857383758408), we obtain a palindrome (99999999999999).
The spelling of 804857383758407 in words is "eight hundred four trillion, eight hundred fifty-seven billion, three hundred eighty-three million, seven hundred fifty-eight thousand, four hundred seven".
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