Base | Representation |
---|---|
bin | 10111011011010100010… |
… | …10001011111001001111 |
3 | 2211221200122111122220102 |
4 | 23231222022023321033 |
5 | 101142004111030112 |
6 | 1413441224241315 |
7 | 112104106410512 |
oct | 13555212137117 |
9 | 2757618448812 |
10 | 804939939407 |
11 | 29041167a34a |
12 | 11000491023b |
13 | 5aba0539846 |
14 | 2ad60470d79 |
15 | 15e11d32bc2 |
hex | bb6a28be4f |
804939939407 has 4 divisors (see below), whose sum is σ = 830905743936. Its totient is φ = 778974134880.
The previous prime is 804939939367. The next prime is 804939939413. The reversal of 804939939407 is 704939939408.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 804939939407 - 212 = 804939935311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (804939939437) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12982902218 + ... + 12982902279.
It is an arithmetic number, because the mean of its divisors is an integer number (207726435984).
Almost surely, 2804939939407 is an apocalyptic number.
804939939407 is a deficient number, since it is larger than the sum of its proper divisors (25965804529).
804939939407 is a wasteful number, since it uses less digits than its factorization.
804939939407 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25965804528.
The product of its (nonzero) digits is 52907904, while the sum is 65.
Subtracting from 804939939407 its reverse (704939939408), we obtain a palindrome (99999999999).
The spelling of 804939939407 in words is "eight hundred four billion, nine hundred thirty-nine million, nine hundred thirty-nine thousand, four hundred seven".
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