Base | Representation |
---|---|
bin | 10111011011100000010… |
… | …00110001101110000111 |
3 | 2211221221122020010022221 |
4 | 23231300020301232013 |
5 | 101142210244431401 |
6 | 1413455210033211 |
7 | 112106435035624 |
oct | 13556010615607 |
9 | 2757848203287 |
10 | 805040233351 |
11 | 290463251702 |
12 | 110032418807 |
13 | 5abb8254083 |
14 | 2ad6d8db34b |
15 | 15e1aa447a1 |
hex | bb70231b87 |
805040233351 has 4 divisors (see below), whose sum is σ = 805079426704. Its totient is φ = 805001040000.
The previous prime is 805040233337. The next prime is 805040233373. The reversal of 805040233351 is 153332040508.
805040233351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 805040233351 - 213 = 805040225159 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (805040233051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19565850 + ... + 19606951.
It is an arithmetic number, because the mean of its divisors is an integer number (201269856676).
Almost surely, 2805040233351 is an apocalyptic number.
805040233351 is a deficient number, since it is larger than the sum of its proper divisors (39193353).
805040233351 is a wasteful number, since it uses less digits than its factorization.
805040233351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39193352.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 805040233351 its reverse (153332040508), we get a palindrome (958372273859).
The spelling of 805040233351 in words is "eight hundred five billion, forty million, two hundred thirty-three thousand, three hundred fifty-one".
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