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80578275553 is a prime number
BaseRepresentation
bin100101100001011010…
…1101110100011100001
321200222122020111221001
41023002311232203201
52310011014304203
6101003412032001
75551543020106
oct1130265564341
9250878214831
1080578275553
113119a377066
1213749602601
1377a1b953b9
143c858a8aad
15216914991d
hex12c2d6e8e1

80578275553 has 2 divisors, whose sum is σ = 80578275554. Its totient is φ = 80578275552.

The previous prime is 80578275527. The next prime is 80578275563. The reversal of 80578275553 is 35557287508.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49971472849 + 30606802704 = 223543^2 + 174948^2 .

It is a cyclic number.

It is not a de Polignac number, because 80578275553 - 213 = 80578267361 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 80578275494 and 80578275503.

It is not a weakly prime, because it can be changed into another prime (80578275523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40289137776 + 40289137777.

It is an arithmetic number, because the mean of its divisors is an integer number (40289137777).

Almost surely, 280578275553 is an apocalyptic number.

It is an amenable number.

80578275553 is a deficient number, since it is larger than the sum of its proper divisors (1).

80578275553 is an equidigital number, since it uses as much as digits as its factorization.

80578275553 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11760000, while the sum is 55.

The spelling of 80578275553 in words is "eighty billion, five hundred seventy-eight million, two hundred seventy-five thousand, five hundred fifty-three".