Base | Representation |
---|---|
bin | 1111000010100000… |
… | …01011000010110001 |
3 | 202211200210210011001 |
4 | 13201100023002301 |
5 | 113013431033213 |
6 | 3413103322001 |
7 | 404040360046 |
oct | 74120130261 |
9 | 22750723131 |
10 | 8074080433 |
11 | 3473676151 |
12 | 1693bb0301 |
13 | 9b89accb3 |
14 | 56846d1cd |
15 | 323c801dd |
hex | 1e140b0b1 |
8074080433 has 2 divisors, whose sum is σ = 8074080434. Its totient is φ = 8074080432.
The previous prime is 8074080409. The next prime is 8074080463. The reversal of 8074080433 is 3340804708.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6220950129 + 1853130304 = 78873^2 + 43048^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-8074080433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 8074080392 and 8074080401.
It is not a weakly prime, because it can be changed into another prime (8074080463) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4037040216 + 4037040217.
It is an arithmetic number, because the mean of its divisors is an integer number (4037040217).
Almost surely, 28074080433 is an apocalyptic number.
It is an amenable number.
8074080433 is a deficient number, since it is larger than the sum of its proper divisors (1).
8074080433 is an equidigital number, since it uses as much as digits as its factorization.
8074080433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64512, while the sum is 37.
The square root of 8074080433 is about 89855.8870247242. The cubic root of 8074080433 is about 2006.1544115998.
The spelling of 8074080433 in words is "eight billion, seventy-four million, eighty thousand, four hundred thirty-three".
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