Base | Representation |
---|---|
bin | 100101101010100111… |
… | …1110100000111000111 |
3 | 21201210011100121211120 |
4 | 1023111033310013013 |
5 | 2311124044311233 |
6 | 101054203205023 |
7 | 5562313016322 |
oct | 1132517640707 |
9 | 251704317746 |
10 | 80887103943 |
11 | 31338730438 |
12 | 13814b16773 |
13 | 7820b646a9 |
14 | 3cb48d97b9 |
15 | 21862ee4b3 |
hex | 12d53f41c7 |
80887103943 has 24 divisors (see below), whose sum is σ = 114910577280. Its totient is φ = 50470845840.
The previous prime is 80887103879. The next prime is 80887103951. The reversal of 80887103943 is 34930178808.
It is not a de Polignac number, because 80887103943 - 26 = 80887103879 is a prime.
It is a super-2 number, since 2×808871039432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (80887103993) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 289678 + ... + 495668.
It is an arithmetic number, because the mean of its divisors is an integer number (4787940720).
Almost surely, 280887103943 is an apocalyptic number.
80887103943 is a gapful number since it is divisible by the number (83) formed by its first and last digit.
80887103943 is a deficient number, since it is larger than the sum of its proper divisors (34023473337).
80887103943 is a wasteful number, since it uses less digits than its factorization.
80887103943 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 206179 (or 206096 counting only the distinct ones).
The product of its (nonzero) digits is 1161216, while the sum is 51.
The spelling of 80887103943 in words is "eighty billion, eight hundred eighty-seven million, one hundred three thousand, nine hundred forty-three".
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