Base | Representation |
---|---|
bin | 10010011010101100101001… |
… | …010011001011100010000001 |
3 | 101121210110211002221002000212 |
4 | 102122230221103023202001 |
5 | 41104043414132112324 |
6 | 444134351541523505 |
7 | 23030006436415235 |
oct | 2232545123134201 |
9 | 347713732832025 |
10 | 80999481129089 |
11 | 238997614996a6 |
12 | 91022aa413595 |
13 | 36272ab799443 |
14 | 16005781325c5 |
15 | 956eb085a70e |
hex | 49ab294cb881 |
80999481129089 has 2 divisors, whose sum is σ = 80999481129090. Its totient is φ = 80999481129088.
The previous prime is 80999481129059. The next prime is 80999481129157. The reversal of 80999481129089 is 98092118499908.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 69122462976064 + 11877018153025 = 8313992^2 + 3446305^2 .
It is a cyclic number.
It is not a de Polignac number, because 80999481129089 - 244 = 63407295084673 is a prime.
It is not a weakly prime, because it can be changed into another prime (80999481129019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40499740564544 + 40499740564545.
It is an arithmetic number, because the mean of its divisors is an integer number (40499740564545).
Almost surely, 280999481129089 is an apocalyptic number.
It is an amenable number.
80999481129089 is a deficient number, since it is larger than the sum of its proper divisors (1).
80999481129089 is an equidigital number, since it uses as much as digits as its factorization.
80999481129089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 241864704, while the sum is 77.
The spelling of 80999481129089 in words is "eighty trillion, nine hundred ninety-nine billion, four hundred eighty-one million, one hundred twenty-nine thousand, eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.084 sec. • engine limits •