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80999627437387 is a prime number
BaseRepresentation
bin10010011010101100110010…
…000001010011010101001011
3101121210111012022020022021201
4102122230302001103111023
541104044214110444022
6444134414245445031
723030013164131111
oct2232546201232513
9347714168208251
1080999627437387
112389982703a24a
12910232b410777
133627302ba4bb9
14160058d739ab1
15956ebd60b127
hex49ab3205354b

80999627437387 has 2 divisors, whose sum is σ = 80999627437388. Its totient is φ = 80999627437386.

The previous prime is 80999627437303. The next prime is 80999627437409. The reversal of 80999627437387 is 78373472699908.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-80999627437387 is a prime.

It is a super-3 number, since 3×809996274373873 (a number of 43 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 80999627437387.

It is not a weakly prime, because it can be changed into another prime (80999621437387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40499813718693 + 40499813718694.

It is an arithmetic number, because the mean of its divisors is an integer number (40499813718694).

Almost surely, 280999627437387 is an apocalyptic number.

80999627437387 is a deficient number, since it is larger than the sum of its proper divisors (1).

80999627437387 is an equidigital number, since it uses as much as digits as its factorization.

80999627437387 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6913299456, while the sum is 82.

The spelling of 80999627437387 in words is "eighty trillion, nine hundred ninety-nine billion, six hundred twenty-seven million, four hundred thirty-seven thousand, three hundred eighty-seven".