Base | Representation |
---|---|
bin | 100101101111010011… |
… | …1101000001111111001 |
3 | 21202012010020010120011 |
4 | 1023132213220033321 |
5 | 2311434322414003 |
6 | 101121541301521 |
7 | 5566232352514 |
oct | 1133647501771 |
9 | 252163203504 |
10 | 81044341753 |
11 | 31409466541 |
12 | 138597048a1 |
13 | 78475c8b0b |
14 | 3ccb749d7b |
15 | 219500d46d |
hex | 12de9e83f9 |
81044341753 has 2 divisors, whose sum is σ = 81044341754. Its totient is φ = 81044341752.
The previous prime is 81044341691. The next prime is 81044341771. The reversal of 81044341753 is 35714344018.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 73071280489 + 7973061264 = 270317^2 + 89292^2 .
It is a cyclic number.
It is not a de Polignac number, because 81044341753 - 213 = 81044333561 is a prime.
It is a super-3 number, since 3×810443417533 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (81044341453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 40522170876 + 40522170877.
It is an arithmetic number, because the mean of its divisors is an integer number (40522170877).
Almost surely, 281044341753 is an apocalyptic number.
It is an amenable number.
81044341753 is a deficient number, since it is larger than the sum of its proper divisors (1).
81044341753 is an equidigital number, since it uses as much as digits as its factorization.
81044341753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 161280, while the sum is 40.
The spelling of 81044341753 in words is "eighty-one billion, forty-four million, three hundred forty-one thousand, seven hundred fifty-three".
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