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81130266115800 = 233521123599058559
BaseRepresentation
bin10010011100100110011100…
…101100010011111011011000
3101122020222101201221202222120
4102130212130230103323120
541113214241111201200
6444314421342021240
723042316424436466
oct2234463454237330
9348228351852876
1081130266115800
112393a175184980
129123709b77820
133636722198445
141606a23979836
1595a5b757c9a0
hex49c99cb13ed8

81130266115800 has 384 divisors, whose sum is σ = 291149365248000. Its totient is φ = 18493952012800.

The previous prime is 81130266115781. The next prime is 81130266115813. The reversal of 81130266115800 is 851166203118.

81130266115800 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4426921 + ... + 13485479.

It is an arithmetic number, because the mean of its divisors is an integer number (758201472000).

Almost surely, 281130266115800 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 81130266115800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (145574682624000).

81130266115800 is an abundant number, since it is smaller than the sum of its proper divisors (210019099132200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

81130266115800 is a wasteful number, since it uses less digits than its factorization.

81130266115800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9058671 (or 9058662 counting only the distinct ones).

The product of its (nonzero) digits is 69120, while the sum is 42.

The spelling of 81130266115800 in words is "eighty-one trillion, one hundred thirty billion, two hundred sixty-six million, one hundred fifteen thousand, eight hundred".