Base | Representation |
---|---|
bin | 10111100111001110010… |
… | …00100010000010011001 |
3 | 2212120012002120221100122 |
4 | 23303213020202002121 |
5 | 101243101344000423 |
6 | 1420415352243025 |
7 | 112421361011642 |
oct | 13634710420231 |
9 | 2776162527318 |
10 | 811331625113 |
11 | 2930a1607429 |
12 | 1112a93a0475 |
13 | 5b67b7c56a9 |
14 | 2b3a92bc6c9 |
15 | 1618803a8c8 |
hex | bce7222099 |
811331625113 has 2 divisors, whose sum is σ = 811331625114. Its totient is φ = 811331625112.
The previous prime is 811331625089. The next prime is 811331625149. The reversal of 811331625113 is 311526133118.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 747095736409 + 64235888704 = 864347^2 + 253448^2 .
It is a cyclic number.
It is not a de Polignac number, because 811331625113 - 224 = 811314847897 is a prime.
It is not a weakly prime, because it can be changed into another prime (811331625413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 405665812556 + 405665812557.
It is an arithmetic number, because the mean of its divisors is an integer number (405665812557).
Almost surely, 2811331625113 is an apocalyptic number.
It is an amenable number.
811331625113 is a deficient number, since it is larger than the sum of its proper divisors (1).
811331625113 is an equidigital number, since it uses as much as digits as its factorization.
811331625113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12960, while the sum is 35.
The spelling of 811331625113 in words is "eight hundred eleven billion, three hundred thirty-one million, six hundred twenty-five thousand, one hundred thirteen".
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