Base | Representation |
---|---|
bin | 111011000010011101111… |
… | …1010010111000111100011 |
3 | 1001201201011102210000200021 |
4 | 1312010323322113013203 |
5 | 2030420334241030211 |
6 | 25131340011334311 |
7 | 1465142254130533 |
oct | 166047372270743 |
9 | 31651142700607 |
10 | 8114198376931 |
11 | 26492374a1049 |
12 | ab0704751397 |
13 | 46b21cb4c06a |
14 | 200a2d2954c3 |
15 | e110791b771 |
hex | 7613be971e3 |
8114198376931 has 2 divisors, whose sum is σ = 8114198376932. Its totient is φ = 8114198376930.
The previous prime is 8114198376881. The next prime is 8114198376989. The reversal of 8114198376931 is 1396738914118.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 8114198376931 - 215 = 8114198344163 is a prime.
It is a super-2 number, since 2×81141983769312 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 8114198376931.
It is not a weakly prime, because it can be changed into another prime (8114198376631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4057099188465 + 4057099188466.
It is an arithmetic number, because the mean of its divisors is an integer number (4057099188466).
Almost surely, 28114198376931 is an apocalyptic number.
8114198376931 is a deficient number, since it is larger than the sum of its proper divisors (1).
8114198376931 is an equidigital number, since it uses as much as digits as its factorization.
8114198376931 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7838208, while the sum is 61.
The spelling of 8114198376931 in words is "eight trillion, one hundred fourteen billion, one hundred ninety-eight million, three hundred seventy-six thousand, nine hundred thirty-one".
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